Question

Решите уравнение 4(x-3)^2=(x+6)^2

Answer 1

$4(x-3)^2=(x+6)^2\\2^2(x-3)^2-(x+6)^2=0\\Big (2(x-3)-(x+6)Big )cdot Big (2(x-3)+(x+6)Big )=0\\Big (x-12Big )cdot Big (3x+0Big )=0\\3xcdot (x-12)=0\\x-12=0; ; ,; ; 3x=0\\underline {x_1=12; ,; ; x_2=0}$