Question

Решите уравнение
(3x-2)*(2x+3)-6(x-1)²=5



(-2x+7)*(x+2)+2*(x+1)²=2

Answer 1

Ответ:

1) x = 1

2) x = -2

Объяснение:

1) (3·x-2)·(2·x+3)-6·(x-1)² = 5

6·x²+9·x-4·x-6-6·(x²-2·x+1) = 5

6·x²+5·x-6-6·x²+12·x-6 = 5

5·x+12·x = 5+6+6

17·x = 17

x = 17:17

x = 1.

2) (-2·x+7)·(x+2)+2·(x+1)² = 2

-2·x²-4·x+7·x+14+2·(x²+2·x+1) = 2

-2·x²+3·x+14+2·x²+4·x+2 = 2

3·x+4·x = 2-14-2

7·x = -14

x = -14:7

x = -2.

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