Question

Решите уравнение
2x²-7x-4/2x²+x
За ранее спасибо

Answer 1

$frac{2x^{2}-7x-4 }{2x^{2}+x } \\2x^{2}-7x-4=0\\D=(-7)^{2}-4*2*(-4)=49+32=81=9^{2}\\x_{1}=frac{7+9}{4} =4\\x_{2}=frac{7-9}{4}=-frac{1}{2}\\2x^{2}-7x-4=2(x-4)(x+frac{1}{2})=(x-4)(2x+1)\\frac{2x^{2}-7x-4 }{2x^{2}+x }=frac{(x-4)(2x+1)}{x(2x+1)}=frac{x-4}{x}$