Question

Решите уравнение 2sin(2x +п /5(дробь)) = √2

Answer 1

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Answer 2

$2 sin frac{2x + pi}{5} = sqrt{2} \ sin frac{2x + pi}{5} = frac{ sqrt{2} }{2} \ frac{2x + pi}{5} = ( -1 ) {}^{n} frac{pi}{4} + pi : n \ 2x + pi = ( - 1) {}^{n} frac{5pi}{4} + 5pi : n \ 2x = - pi + ( - 1) {}^{n} frac{5pi}{4} + 5pi : n \ x = - frac{pi}{2} + ( - 1) {}^{n} frac{5pi}{8} + frac{5pi}{2} n$

где n целое число