Question

решите систему уравнений пожалуйста!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

х=1-4у

$frac{3}{1-4y} +frac{2}{y} =1\ \ frac{3y+2-8y}{y-4y^{2} } =1\ \ -5y+2=y-4y^{2} \ \ 4y^{2} -6y+2=0\ \ 2y^{2} -3y+1=0\ \ d=9-8=1\ \ y1=3-1/4=2/4=1/2\ \ y2=1\ \ \ x1=1-4*1/2=-1\ \ x2=1-4*1=-3$