Question

Решите систему линейных уравнений: {2(4x-y)+3(4x+y)=32. {5(4x-y)-2(4x+y)=4

Answer 1

$left { {2(4x-y)+3(4x+y)=32} atop {5(4x-y)-2(4x+y)=4}} right.$

1)
$2(4x-y)+3(4x+y)=32$
$8x-2y+12x+3y=32$
$20x+y=32$

2)
$5(4x-y)-2(4x+y)=4$
$20x-5y-8x-2y=4$
$12x-7y=4$

$left { {{20x+y=32} atop {12x-7y=4}} right. left { {{y=32-20x} atop {12x-7y=4}} right.$

$12x-7(32-20x)=4$
$12x-224+140x=4$
$-128x=228$
$x= -frac{228}{128}$
$x= -frac{57}{32}$
$x= -1frac{25}{32}$

$y=32-20* (-1frac{25}{32} )$
$y = 32+ frac{285}{8}$
$y=32+35 frac{5}{8}$
$y=67 frac{5}{8}$

Ответ: $-1 frac{25}{32};67 frac{5}{8}$