Question

Решите систему двух неравенств:
{5х+7˂ 4х+8,
2х+7˂ 0.

Answer 1

$\left \{ {{5x+7<4x+8} \atop {2x+7<0}} \right.\\\\\left \{ {{5x-4x<8-7} \atop {2x<-7}} \right.\\\\\left \{ {{x<1} \atop {x<-3,5}} \right.\Rightarrow x<-3,5\\\\Otvet:\boxed{x\in(-\infty;-3,5)}$