Question

Решите систему: 2xy=1
4y-x=1

Answer 1

x=4y-1
2y*(4y-1)=1
8y²-2y-1=0
D=4+32=36
y1=(2-6)/16=-1/4⇒x1=4*(-1/4)-1=-1-1=-2
y2=(2+6)/16=1/2⇒x2=4(1/2-1=2-1=1
(-2;-1/4)  (1;1/2)