Question

решите пж...
$1)5( x - 4) = 3x - 10 \\ 2)4y + 2 = 3(10 - y) \\ 3)7(x - 4) = 5(x + 4) \\ 4)3(y + 1) = 6(1 - y) + 6 \\ 5)2(x - 3) - 3(4 - x) = 5 \\ 6)7 + 4(3 - y) = 5(y + 2)$
вот.​

Answer 1

5(x-4)=3x-10

5x-20=3x-10

5x-3x=-10+20

2x=10

x=5

4y+2=3(10-y)

4y+2=30-3y

4y+3y=30-2

7y=28

y=4

7x-28=5x+20

7x-5x=20+28

2x=48

x=24