Question

Решите пж
4x^3+3x^2=0
x^2-4x+4=0
(x-7)^2+2(x-7)=0

Answer 1

$1) x^2(4x+3)=0\ left[begin{gathered} x=0\ x=-3/4 end{gathered}right.\ 2) x^2-4x+4=0\ (x-2)^2=0\ x=2\ 3)(x-7)^2+2(x-7)=0\ (x-7)(x-7+2)=0\ (x-7)(x-5)=0\ left [ begin{gathered} x=7\ x=5 end{gathered}right.$

Answer 2

1)
4x^3+3^2=0
x^2*(4x+3)=0
x^2=0
x=0
4x+3=0
x=-0,75
2)
x^2-4x+4=0
(x-2)^2=0
x-2=0
x=2
3)
(x-7)^2+2(x-7)
(x-7)*(x-7+2)=0
(x-7)*(x-5)=0
x-7=0
x=7
x-5=0
x=5
x1=5; x2=7