Алгебра, вопрос задал lcidudy , 7 лет назад

решите пример пазазки<З卄丂フ丂g҈g҈d҈ꁅꀷꋪ​

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Ответы на вопрос

Ответил Аноним
0

Объяснение:

(\frac{2}{15}  + 1 \frac{7}{12} )  \times  \frac{30}{103}  - (2 \div 2 \frac{1}{4} ) \times  \frac{9}{32}  =\left(\frac{2}{15}+\frac{12+7}{12}\right)\times \left(\frac{30}{103}\right)-\frac{2}{\frac{2\times 4+1}{4}}\times \left(\frac{9}{32}\right) =\left(\frac{2}{15}+\frac{19}{12}\right)\times \left(\frac{30}{103}\right)-\frac{2}{\frac{2\times 4+1}{4}}\times \left(\frac{9}{32}\right) =\left(\frac{8}{60}+\frac{95}{60}\right)\times \left(\frac{30}{103}\right)-\frac{2}{\frac{2\times 4+1}{4}}\times \left(\frac{9}{32}\right) =  \frac{8+95}{60}\times \left(\frac{30}{103}\right)-\frac{2}{\frac{2\times 4+1}{4}}\times \left(\frac{9}{32}\right) = \frac{103}{60}\times \left(\frac{30}{103}\right)-\frac{2}{\frac{2\times 4+1}{4}}\times \left(\frac{9}{32}\right) =\frac{103\times 30}{60\times 103}-\frac{2}{\frac{2\times 4+1}{4}}\times \left(\frac{9}{32}\right) =\frac{30}{60}-\frac{2}{\frac{2\times 4+1}{4}}\times \left(\frac{9}{32}\right) =\frac{1}{2}-\frac{2}{\frac{2\times 4+1}{4}}\times \left(\frac{9}{32}\right) =\frac{1}{2}-\frac{2\times 4}{2\times 4+1}\times \left(\frac{9}{32}\right) =\frac{1}{2}-\frac{8}{2\times 4+1}\times \left(\frac{9}{32}\right) =\frac{1}{2}-\frac{8}{8+1}\times \left(\frac{9}{32}\right) = \frac{1}{2}-\frac{8}{9}\times \left(\frac{9}{32}\right) =\frac{1}{2}-\frac{8\times 9}{9\times 32} =\frac{1}{2}-\frac{8}{32} =\frac{1}{2}-\frac{1}{4} =\frac{2}{4}-\frac{1}{4} =\frac{2-1}{4} =\frac{1}{4}


MizoriesKun: как так ???
MizoriesKun: правильно ниже ))
Ответил MizoriesKun
0

= (\frac{8}{60} +1\frac{35}{60}  )*\frac{30}{103} -(2:\frac{9}{4} )*\frac{9}{32} =\\\\=(1\frac{43}{60} )*\frac{30}{103} -(2*\frac{4}{9} )*\frac{9}{32} =

= \frac{103}{60} *\frac{30}{103} -\frac{8}{9} *\frac{9}{32} =\\\\=\frac{1}{2} -\frac{1}{4} =\frac{2}{4} -\frac{1}{4} = \frac{1}{4}

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