Question

Решите пожалуйста уравнения
1)4^(-x)-7*2^(-x)=-4
2)128*16^(2x+1)=8^(3-2x)

Answer 1

$128 times {16}^{(2x + 1)} = {8}^{(3 - 2x)} \ {2}^{7} times {2}^{(8x + 4)} = {2}^{(9 - 6x)} \ {2}^{(8x + 11)} = {2}^{(9 - 6x)} \ 8x + 11 = 9 - 6x \ 8x + 6x = 9 - 11 \ 14x = - 2 \ x = - frac{2}{14} \ x= - frac{1}{7}$