Question

решите пожалуйста
$sqrt{ log_{16}4 + log_{16}24- log_{16} 6 }$

Answer 1

$sqrt{log_{16}4+log_{16}24-log_{16}6}= \ \ = sqrt{log_{16}(4*24)-log_{16}6}= \ \ = sqrt{log_{16}(96)-log_{16}6}= \ \ = sqrt{log_{16} (frac{96}{6}) }= \ \ = sqrt{log_{16}16}=1$