Question

Решите пожалуйста систему))

Answer 1

$x - 5y = 3 \ xy + 3y = 11 \ x = 3 + 5y \ y(3 + 5y) + 3y= 11 \ 3y + 5 {y}^{2} + 3y = 1 \ 5 {y}^{2} + 6y - 11 = 0 \ d = 36 + 4 times 5 times 11 = 256 \ y1 = frac{ - 6 + 16}{10} = 1 \ y2 = frac{ - 6 - 16}{10} = - 2.2 \ x1 = 3 + 5 times 1 = 8 \ x2 = 3 + 5 times ( - 2.2) = - 8$