Question

Решите,пожалуйста,подробно логарифм

Answer 1

$displaystyle log^2_{ sqrt{2}}(2 sqrt{2})^{ sqrt{32}}=(log_{ sqrt{2}}( sqrt{2}^3)^{ sqrt{32}})^2 =(log_{ sqrt{2}}( sqrt{2})^{3 sqrt{32}})^2=$

$displaystyle =(3 sqrt{32})^2=9*32= 288$