Question

Решите пожалуйста!!!
3в-(5а-7в)
-3q-(8р-3q)
-(8c-4)+4
-(2a-4)-(3+5a)
(5-3в)+(-3в-11)

Answer 1

3в-(5а-7в)=3в-5а+7в=10в-5а
-3q-(8p-3q=-3q-8p+3q=-8p
-(8c-4)+4=-8c+4+4=8-8c
-(2а-4)-(3+5а)=-2а+4-3-5а=-7а+1
(5-3в)+(-3в-11)=5-3в-3в-11=-6в-6

Answer 2

3в-(5а-7в) = 3b-5a+7b = 10b - 5a
-3q-(8р-3q) = -3q-8p+3q = -8p
-(8c-4)+4 = -8c+4 +4 = -8c+8 = 8(1-c)
-(2a-4)-(3+5a) = -2a+4 -3 -5a =1-7a
(5-3в)+(-3в-11) = 5-3b-3b-11 = -6b - 6 = -6(b+1)