Question

Решите пожалуйста!!!!!

Answer 1

$64z+64-z^{3}-z^{2}=0\64(z+1)-z^{2}(z+1)=0\(64-z^{2})(z+1)=0\(8-z)(8+z)(z+1)=0$

$8-z=0\z=8\\8+z=0\z=-8\\z+1=0\z=-1$

$z_{1}=8\z_{2}=-8\z_{3}=-1$