Question

Решите пожалуйста №3) СРОЧНО!!!

Answer 1

$frac{3y^{2} - 12 }{2y ^{2} - 15y + 18 } times frac{6 - y}{y + 2} + frac{y}{3 - 2y} = \ = frac{3(y ^{2} - 4)}{2y^{2} - 3y - 12y + 18 } times frac{ - (y - 6)}{y + 2} + frac{y}{ - (2y - 3)} = \ = frac{3(y - 2)(y + 2)}{y(2y - 3) - 6(2y - 3)} times frac{ - (y - 6)}{y + 2} - frac{y}{2y - 3} = \ = frac{3(y - 2)(y + 2)}{(2y - 3)(y - 6)} times frac{ - (y - 6)}{y + 2} - frac{y}{2y - 3} = \ = frac{3(y - 2)}{2y - 3} times( - 1) + frac{y}{2y - 3} = \ = - frac{3y - 6 + y}{2y - 3} = - frac{4y - 6}{2y - 3} = \ = - frac{2(2y - 3)}{2y - 3} = - 2$