Question

Решите пожалуйста.............

Answer 1

$begin{cases}x^3-y^3=218,\ x^2+xy+y^2=109;end{cases},begin{cases}(x-y)(x^2+xy+y^2)=218,\ x^2+xy+y^2=109;end{cases}\ begin{cases}x-y=2,\ x^2+xy+y^2=109;end{cases},begin{cases}x=y+2,\ (y+2)^2+(y+2)y+y^2=109;end{cases}\ y^2+4y+4+y^2+2y+y^2=109;\ 3y^2+6y-105=0;,|:3\ y^2+2y-35=0;\ begin{cases}y_1=5,\ x_1=7;end{cases}, begin{cases}y_2=-7,\ x_2=-5.end{cases},$