Решите пожалуйста!!!
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Ответы на вопрос
Ответил UniPie
0
Вот первый пример
![1 + sqrt{x+1} = x -4 \
(sqrt{x+1})^{2} = (x-5)^{2} \
x+1=x^2-10x+25 \
x+1-x^2+10x-25=0 \
x^2-11x+24=0 \
x_1 = 3 \
x_2=8](https://tex.z-dn.net/?f=1+%2B++sqrt%7Bx%2B1%7D++%3D+x+-4+%5C+%0A%28sqrt%7Bx%2B1%7D%29%5E%7B2%7D+%3D+%28x-5%29%5E%7B2%7D+%5C%0Ax%2B1%3Dx%5E2-10x%2B25+%5C%0Ax%2B1-x%5E2%2B10x-25%3D0+%5C%0Ax%5E2-11x%2B24%3D0+%5C+%0Ax_1+%3D+3++%5C%0Ax_2%3D8 "1 + sqrt{x+1} = x -4 \
(sqrt{x+1})^{2} = (x-5)^{2} \
x+1=x^2-10x+25 \
x+1-x^2+10x-25=0 \
x^2-11x+24=0 \
x_1 = 3 \
x_2=8")
Второй пример
![sqrt{x-1} - sqrt{2x-9} = -1 \
(sqrt{x-1} + 1)^2 = (2x-9)^2 \
x-1+2 sqrt{x-1} + 1 = 2x-9\
(2 sqrt{x-1})^2=(x-9)^2 \
4x-4=x^2-18x+81 \
x^-22x+85=0 \
x_1= 5 \
x_2 = 17](https://tex.z-dn.net/?f=+sqrt%7Bx-1%7D++-++sqrt%7B2x-9%7D++%3D+-1+%5C%0A+%28sqrt%7Bx-1%7D+%2B+1%29%5E2+%3D++%282x-9%29%5E2+%5C%0Ax-1%2B2+sqrt%7Bx-1%7D+%2B+1+%3D+2x-9%5C+%0A%282+sqrt%7Bx-1%7D%29%5E2%3D%28x-9%29%5E2+%5C%0A4x-4%3Dx%5E2-18x%2B81+%5C%0Ax%5E-22x%2B85%3D0+%5C%0Ax_1%3D+5+%5C%0Ax_2+%3D+17 "sqrt{x-1} - sqrt{2x-9} = -1 \
(sqrt{x-1} + 1)^2 = (2x-9)^2 \
x-1+2 sqrt{x-1} + 1 = 2x-9\
(2 sqrt{x-1})^2=(x-9)^2 \
4x-4=x^2-18x+81 \
x^-22x+85=0 \
x_1= 5 \
x_2 = 17")
Второй пример
Ответил UniPie
0
В первом один корень - это 8
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