Question

Решите пожалуйста, 10-11 класс

Answer 1

Ответ:

Объяснение:

2^(5,3) ·2^(-0,3)=2^(5,3-0,3)=2⁵=32

7^(-1/2) ·7^(3,5)=7^(-0,5+3,5)=7³=343

3^(6,8) ·3(-5,8)=3^(6,8-5,8)=3¹=3

(3/4)^(3,7) ·(3/4)^(-0,7)=(3/4)^(3,7-0,7)=(3/4)³=27/64=0,421875

4^(3,5) ÷4³=4^(3,5-3)=4^(0,5)=4^(1/2)=√4=2

(1/2)^(-6,3) ÷(1/2)^(-2,3)=(1/2)^(-6,3+2,3)=(1/2)⁻⁴=2⁴=16

8^(2 1/3) ÷8²=8^(2 1/3 -2)=8^(1/3)=∛8=2

(2/3)^(2,4) ÷(2/3)^(-0,6)=(2/3)^(2,4+0,6)=(2/3)³=8/27

(2^1/3)⁶=2^(1/3·6)=2²=4

((1/7)²)^(1/2)=(1/7)^(2·1/2)=(1/7)¹=1/7

(3 3/2)²=(9/2)²=81/4=20 1/4=20,25

((3/4)^(1/3))⁻¹=(3/4)^(1/3 ·(-1))=(3/4)^(-1/3)=(4/3)^(1/3)=∛(4/3)=∛(2²/3)=(2^(2/3))/3^(1/3)=(2^(2/3) ·3^(2/3))/(3^(1/3) ·3^(2/3))=(6^(2/3))/(3^(1/3 +2/3))=(∛6²)/3^(3/3)=(∛36)/3