Question

решите пожалуйста
1) 6^x= √6
2)
$sqrt[3]{128} = 2 {}^{3x}$

Answer 1

$1)6^{x}=6^{frac{1}{2}} \\x=frac{1}{2}$

$2)128^{frac{1}{3}}=2^{3x}\\2^{frac{7}{3}}=2^{3x}\\frac{7}{3}=3x\\x=frac{7}{9}$

Answer 2

${6}^{x} = sqrt{6} \ {6}^{x} = 6 {}^{ frac{1}{2} } \ x = 0.5 [tex] - - - - - \ sqrt[3]{128} = 2 {}^{3x} \ 2 {}^{ frac{7}{3} } = 2 {}^{3x} \ 3x = frac{7}{3} \ x = frac{7}{9}$