Question

Решите подробно кккк

Answer 1

$frac{9x^2-3xy}{12xy-4y^2}= frac{3x(3x-y)}{4y(3x-y)} = frac{3x}{4y} = frac{3*0.5}{4*0.25} =1.5$

Answer 2

$frac{9 x^{2} -3xy}{12xy-4y^{2}}= frac{3x(3x-y)}{4y(3x-y)} = frac{3x}{4y} = frac{3*0,5}{4*0,25}=1,5$