Question

решите неравенство $frac{x^{2}+x-6 }{x-9} geq 0$

Answer 1

$sf displaystyle frac{x^2+x-6}{x-9}geq 0\\y=frac{x^2+x-6}{x-9}\y=0\ frac{x^2+x-6}{x-9}=0\x^2+x-6=0\D=b^2-4ac=1+24=25=5^2\x_{1,2}=frac{-1pm 5}{2}=left |{ {{2} atop {-3}} right. \x=-3;x=2;xneq 9\---[-3]+++[2]---(9)+++>x\xin [-3;2] cup (9;+infty)$

Ответ: $[-3;2] cup (9;+infty)$