решите неравенство логорифма
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Ответы на вопрос
Ответил Ivanna2013
0
log_5(x+12)>=log_5(4x+3)
![log_5(x+12)>=log_5(4x+3)\
x+12>=4x+3\
x+12>0\
4x+3>0\
3x<=9\x>-12\
4x>-3\
x<=3\x>-12\x>-3/4\
(-3/4;3]\C](https://tex.z-dn.net/?f=log_5%28x%2B12%29%26gt%3B%3Dlog_5%284x%2B3%29%5C%0Ax%2B12%26gt%3B%3D4x%2B3%5C%0Ax%2B12%26gt%3B0%5C%0A4x%2B3%26gt%3B0%5C%0A3x%26lt%3B%3D9%5Cx%26gt%3B-12%5C%0A4x%26gt%3B-3%5C%0Ax%26lt%3B%3D3%5Cx%26gt%3B-12%5Cx%26gt%3B-3%2F4%5C%0A%28-3%2F4%3B3%5D%5CC "log_5(x+12)>=log_5(4x+3)\
x+12>=4x+3\
x+12>0\
4x+3>0\
3x<=9\x>-12\
4x>-3\
x<=3\x>-12\x>-3/4\
(-3/4;3]\C")
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