Question

Решите неравенство
log₅ (3x+2) < 2

Answer 1

log₅ (3x+2) < 2
$ODZ:x textgreater -2/3 \ \ log_{5} (3x+2) textless log_{5} 25 \ \ 5 textgreater 1 \ \ 3x+2 textless 25 \ \ 3x textless 23 \ \ x textless 23/3 \ \ otvet: - frac{2}{3} textless x textless 7 frac{2}{3}$