Question

решите неравенство х2+6х≤0
б) 2х2- х-6 ≤0

Answer 1

$1) x^{2} + 6x le 0 \ \ x(x + 6) le 0 \ \ x in [-6;0] (1) \ \ 2) 2x^{2} - x -6 le 0 \ D = 1 +48 = 49 \ \ x_{1} = dfrac{1 + 7}{4} = 2 ; x_{2} = dfrac{1-7}{4} = -1.5 \ \ x in [-dfrac{3}{2};2] (2)$