Question

Решите неравенство: (9x-7)^2-10≤(9x+3)•(9x-5)

Answer 1

$displaystyle tt (9x-7)^2-10leq (9x+3)(9x-5)\displaystyle tt 81x^2-126x+49-10leq 81x^2-45x+27x-15\displaystyle tt -126x+49-10leq -45x+27x-15\displaystyle tt -126x+39leq -18x-15\displaystyle tt -126x+18xleq -15-39\displaystyle tt -108xleq -54\displaystyle tt xgeq frac{54}{108}\displaystyle tt xgeq frac{1}{2}\displaystyle tt xgeq 0,5\\displaystyle tt underline{bold{xin[frac{1}{2}; : +infty)}}$