Question

решите неравенства:$a) 4^{5-2x} leq 0,25 b) log_{5} (3x+1) >2$

Answer 1

$a) 4^{5-2x} leq 0.25 4^{5-2x}leq 1/4 4^{5-2x}leq 4^{-1} 5-2x leq -1 -2x leq -6 2x geq 6 x geq 3 Answer: x geq 3$
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$b) log_5(3x+1) textgreater 2 log_5(3x+1) textgreater log_5( 5^{2}) 3x+1 textgreater 25 3x textgreater 24 x textgreater 8 Answer: x textgreater 8$