Question

Решите методом интервалов

Answer 1

$(x+7)(x-5)<0\xin (-7;5)\\x^2-121 geq 0\(x-11)(x+11) geq 0\xin (-infty; -11)cup (11;+infty)\\-x^2+11x+60 geq 0\(x+4)(x-15) leq 0\xin [-4;15]\\3x^2-2mx+12=0\D=4m^2-144\D<0\m^2-36<0\(m-6)(m+6)<0\min (-6;6)$