Question

Решите хотя-бы 10 пожалуйста ​

Answer 1

Объяснение:

$1.\ (2ac)^0=1.\\2.\ 3^0+3^0=1+1=2.\\3.\ 3^1=3.\\4.\ 2^2=4.\\5. \ 5^{11}:5^{10}=5^1=5.\\6.\ \frac{(2*3)^5}{6^4} =\frac{6^5}{6^4}=6^1=6.\\7.\ \frac{7^8}{7^7}=7^1=7.\\ 8.\ \frac{2^{12}}{2^9}=2^3=8.\\ 9.\ \frac{3^{11}}{27^3}=\frac{3^{11}}{(3^3)^3}=\frac{3^{11}}{3^9}=3^2=9.$

$10.\\\frac{10^{15}*10^7}{10^{21}}=\frac{10^{15+7}}{10^{21}} =\frac{10^{22}}{10^{21}}=10^{22-21}=10^1=10.$