Question

Решите Алгебра Срочно Пожалуйста

Answer 1

1) $frac{1}{6}sqrt{144} =frac{1}{6}*12=frac{12}{6}=2$

2) $2,1+1,3*sqrt{frac{81}{169}}=2,1 +1,3*frac{9}{13}=2,1+frac{13}{10}*frac{9}{13}=2,1+frac{13*9}{10*13}=frac{21}{10}+frac{9}{10}=frac{30}{10}=3$

3) $(0,4sqrt{5} )^{2}=0,4^{2}*5=(frac{4}{10})^{2}*5=frac{16}{100}*frac{5}{1}=frac{16*5}{100*1}=frac{16}{25}=frac{4}{5}=0,8$

4) $sqrt{225*0,04}=15*0,2=3$

5) $sqrt{28}*sqrt{63}=sqrt{4*7}*sqrt{9*7}=2sqrt{7}*3sqrt{7}=6(sqrt{7} )^{2}=6*7=42$

6) $frac{sqrt{48}}{sqrt{3}}=frac{sqrt{16*3}}{sqrt{3}}=frac{4sqrt{3}}{sqrt{3}}=4$

7) $sqrt{2^{6}*7^{2}}=2^{3}*7=8*7=56$

8) $x^{2}=0,09\x=+-sqrt{0,09}\x=+-0,3$

9) $x^{2}=92\x=+-sqrt{92}\x=+-sqrt{4*23}\x=+-2sqrt{23}$

10) $frac{1}{7}x^{2}sqrt{49x^{6}}=frac{1}{7}x^{2}*7x^3=frac{1*7}{7*1}x^{2+3}=x^{5}$

11) $-5y^{6}sqrt{frac{1}{81y^{10}}}=-5y^{6}*frac{1}{9y^{5}}=-frac{5y^{6}*1}{1*9y^{5}}=-frac{5y}{9}$