Question

Решите 1 вариант пожалуйста срочно даю 50 баллов

Answer 1

Ответ:

$1)y' = 2(7x + 2) \times 7 - 20 {x}^{3} = \\ = 14(7x + 2) - 20 {x}^{3} = \\ = 98x + 28 - 20 {x}^{3}$

$2)y' = \frac{2(15 {x}^{3} + 4x) \times (45 {x}^{2} + 4) }{2} = (45 {x}^{2} + 4)(15 {x}^{3} + 4x)$

$3)y' = \frac{1}{ {x}^{3} } \times 3 {x}^{2} = \frac{3}{x}$

$4)y' = {e}^{ \cos(x) } \times ( - \sin(x))$

$5)y' = - \sin(5 {x}^{4} - 2 ) \times 20 {x}^{3} = \\ = - 20 {x}^{3} \sin(5 {x}^{4} - 2 )$

$6)y' = \cos(4 {x}^{3} ) \times 12 {x}^{2}$

$7)y = \sqrt{ {(2x + 4)}^{4} } = {(2x + 4)}^{2} \\ y' = 2(2x + 4) \times 2 = \\ = 8x + 16$

$8)y' = 5 {x}^{4} + \sin(8 {x}^{3} + 5 ) \times 24 {x}^{2}$

$9)y' = 6 \times ( - 3) { \sin }^{ - 4} (x )\times \cos(x) = \\ = - \frac{18 \cos(x) }{ { \sin }^{4}(x) }$

$10)y' = \frac{1}{ { \cos}^{2}(3 {x}^{4} - 9 {x}^{3}) } \times (12 {x}^{3} - 27 {x}^{2} )$