Question

Решить в 1.203 А,Е

Answer 1

$a) {( sqrt{20} + sqrt{5}) }^{2} = { sqrt{20} }^{2} + 2 sqrt{20 times 5} + { sqrt{5} }^{2} = 20 + 2 sqrt{100} + 5 = 25 + 20 = 45 \ e) {( sqrt{0.18} + sqrt{0.08} ) }^{2} = 0.18 + 2 sqrt{0.0144} + 0.08 = 0.26 + 2 times 0.12 = 0.26 + 0.24 = 0.5$

Answer 2

$(sqrt{20}+sqrt{5})^2=(sqrt{4cdot 5}+sqrt{5})^2=(2sqrt{5}+sqrt{5})^2= (3sqrt{5})^2=9cdot 5=45$

$(sqrt{0,18}+sqrt{0,08})^2=left(sqrt{frac{9cdot 2}{100}}+sqrt{frac{4cdot 2}{100}}right)^2=left(frac{3sqrt{2}}{10}+frac{2sqrt{2}}{10}right)^2= left(frac{5sqrt{2}}{10}right)^2=$

$=left(frac{sqrt{2}}{2}right)^2=frac{2}{4}=frac{1}{2}=0,5$

Ответ: а) 45; е) 0,5