Question

Решить уравнение 5/(x^2-7x)-(x-5)/(x^2+7x)-9/(x^2-49)=0

Answer 1

$frac{5}{x^{2}-7x }-frac{x-5}{x^{2}+7x }-frac{9}{x^{2}-49 }=0\\frac{5}{x(x-7)}-frac{x-5}{x(x+7)}-frac{9}{(x-7)(x+7)}=0\\frac{5x+35-x^{2}+5x+7x-35-9x^{2}}{x(x-7)(x+7)}=0\\frac{-10x^{2}+17x }{x(x-7)(x+7)}=0\\xneq0;xneq-7;xneq7\\-10x^{2}+17x=0\\10x^{2}-17x=0\\ x(10x-17)=0\\xneq 0\\10x-17=0\\10x=17\\x=1,7$

Ответ: 1,7