Question

Решит уравнение: 2(х+1)-(х+1)(х^2+х) =0

Answer 1

$(x + 1)(2 - ( {x}^{2} + x)) = 0 \ (x + 1)(2 - {x}^{2} - x) = 0 \ (x + 1)( - {x}^{2} - x + 2) = 0 \ (x + 1)( - {x}^{2} + x - 2x + 2) = 0 \ (x + 1)( - x times (x - 1) - 2(x - 1)) = 0 \ (x + 1)( - (x - 1))(x + 2) = 0 \ (x + 1)( - x + 1)(x + 2) = 0 \ x + 1 = 0 \ - x + 1 = 0 \ x + 2 = 0 \ x = - 1 \ x = 1 \ x = - 2 \ \ - - - - - - - - \ \ x1 = - 2 \ x2 = - 3 \ x3 = 1$