Question

Решить систему уравнений x^2+y^2=5 x+y=3

Answer 1

$left { {{x^2+y^2=5} atop {x+y=3}} right. ; left { {{x^2+(3-x)^2=5} atop {y=3-x}} right. ; left { {{2x^2-6x+4=0} atop {y=3-x}} right. ; left { {{x^2-3x+2=0} atop {y=3-x}} right. \\left { {{x_1=1; ,; x_2=2; (teor.; Vieta)} atop {y=3-xqquad qquad qquad }} right. ; left { {{x_1=1; ,; x_2=2} atop {y_1=2; ,; y_2=1}} right. \\Otvet:; ; (1,2); ,; (2,1);.$