Question

Решить неравенство$tg(3x- frac{ pi }{4} )< frac{1}{ sqrt{3} }$

Answer 1

$tg(3x-frac{pi}{4})<frac{1}{sqrt{3}}\\ tg(3x-frac{pi}{4})<frac{sqrt{3}}{3}\\ -frac{pi}{2}+pi*k<3x-frac{pi}{4}<frac{pi}{6}+pi*k$
$-frac{pi}{6}+frac{pi}{12}+frac{pi*k}{3}<x<frac{pi}{18}+frac{pi}{12}+frac{pi*k}{3}\\<span>-frac{pi}{12}+frac{pi*k}{3}<x<frac{5pi}{36}+frac{pi*k}{3}$