Question

решить неравенство $\frac{3x+1}{4x-2} \leq \frac{x+2}{2x-1}$

Answer 1

Ответ:

Объяснение:

$\displaystyle\\\frac{3x+1}{4x-2} \leq \frac{x+2}{2x-1} \\\\\\\frac{3x+1}{2(2x-1)} - \frac{x+2}{2x-1}\leq 0\\\\\\\frac{3x+1-2(x+2)}{2(2x-1)} \leq 0\\\\\\\frac{3x+1-2x-4}{4(x-0,5)} \leq 0\\\\\\\frac{x-3}{4(x-0,5)} \leq 0\\\\znaki:+++(0,5)---[3]+++>x\\\\\boldsymbol{Otvet:x\in(0,5;3]}$