Решить неравенство.
Sin(3/x+pi/12)<√2/2
Ответы на вопрос
Ответил sedinalana
0
3π/4+2πn<3/x+π/12<9π/4+2πn,n∈z
3π/4-π/12+2πn<3/x<9π/4-π/12+2πn,n∈z
2π/3+2πn<3/x<13π/6+2πn,n∈z
18/13π+3/2πn<x<9/2π+3/2πn,n∈z
3π/4-π/12+2πn<3/x<9π/4-π/12+2πn,n∈z
2π/3+2πn<3/x<13π/6+2πn,n∈z
18/13π+3/2πn<x<9/2π+3/2πn,n∈z
Новые вопросы