Question

Решить неравенство:
10^(3х+1) > 0,001
Решить неравенство:
Log6 (5x-2) > 3 log6 2 + 2
Найти производную функции:
Y = (1-4x)^9

Answer 1

$10^{3x+1} textgreater 0.001 \ 10^{3x+1} textgreater 10^{-3} \ 3x+1 textgreater -3 \ 3x textgreater -4 \ x textgreater -frac{4}{3}$

$log_6 (5x-2) textgreater 3log_6 2 + 2 \ 5x-2 textgreater 0; x textgreater 0.4 \ log_6 (5x-2) textgreater log_6 8 + log_6 36 \ log_6 (5x-2) textgreater log_6 288 \ 5x-2 textgreater 288 \ 5x textgreater 290 \ x textgreater 58$

$y=(1-4x)^9 \ y'=9*(1-4x)^8*(-4)=-36(1-4x)^8$