Question

Решить
29+x^2/(6-x)^2 + 2(5x-1)/(x-6)^2 + 5-2x/(6-x)^2 =

Answer 1

$\frac{29 + {x}^{2} }{ {(6 - x)}^{2} } + \frac{2(5x - 1)}{ {(x - 6)}^{2} } + \frac{5 - 2x}{ {(6 - x)}^{2} } = \frac{29 + {x}^{2} }{ {(6 - x)}^{2} } + \frac{10x - 2}{ {(6 - x)}^{2} } + \frac{5 - 2x}{ {(6 - x)}^{2} } = \frac{29 + {x}^{2} + 10x - 2 + 5 - 2x}{ {(6 - x)}^{2} } = \frac{ {x}^{2} + 8x + 32}{ 36 - 12x + {x}^{2} } = \frac{ {x}^{2} + 8x + 32 }{ {x}^{2} - 12x + 36}$

Не получается красивый ответ, как обычно :)

ps: ${(x - 6)}^{2} = {( - 1( - x + 6))}^{2} = {( - 1)}^{2} \times {( - x + 6)}^{2} = 1 \times {(- x + 6)}^{2} = {(6 - x)}^{2}$