Question

реши систему уравнений x+y=2 y+z=-3 z+x=4

Answer 1

$\displaystyle\bf\\+\left\{ \begin{array}{ccc}x+y=2\\y+z=-3\\z+x=4\end{array}\right\\---------\\x+y+y+z+z+x=3\\\\2x+2y+2z=3\\\\\underbrace{x+y}_{2}+z=1.5\\\\2+z=1,5\\\\\boxed{z=-0,5}\\\\\\z+x=4\\\\x=4-z=4-(-0,5)=4+0,5=4,5\\\\\boxed{x=4,5}\\\\\\y+z=-3\\\\y=-3-z=-3-(-0,5)=-3+0,5=-2,5\\\\\boxed{y=-2,5}\\\\\\Otvet: \ x=4,5 \ \ ; \ \ y=-2,5 \ \ ; \ \ z=-0,5$

Answer 2

Объяснение:

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ответ