Question

Реши систему управлений:

3x−4y=0,
−5x+11y=26


Срочно пожалуйста!!!!!!

Answer 1

$3x - 4y = 0 \\ - 5x + 11y = 26 \\ \\ x = (0 + 4y) \div 3 \\ \\ - 5((0 + 4y) \div 3) + 11y = 26 \\ - 5(0 + \frac{4}{3} y) + 11y = 26 \\ 0 - 6 \times \frac{2}{3} y + 11y = 26 \\ 5 \times \frac{2}{3}y = 26 \\ y = 26 \div \frac{17}{3} \\ y = \frac{1}{26} \times \frac{17}{3} \\ y = \frac{17}{78} \\ \\ 3x - 4( \frac{17}{78}) = 0 \\ 3x - \frac{68}{78} = 0 \\ 3x = \frac{68}{78} \\ x = \frac{68}{78} \times \frac{1}{3} \\ x = \frac{34}{117}$