Question

реши пж и распеши(5/6-38):3/4(3/8+7/20):1 9/20 прошу

Answer 1

$(frac{5}{6}-38):frac{3}{4}*(frac{3}{8}+frac{7}{20}):1frac{9}{20}=\(frac{5}{6}-38)*frac{4}{3}*(frac{3}{8}+frac{7}{20}):frac{29}{20}=\(frac{5}{6}-38)*frac{4}{3}*(frac{15}{40}+frac{14}{40})*frac{20}{29}=\(frac{5}{6}-38)*frac{4}{3}*frac{29}{40}*frac{20}{29}=\(frac{5}{6}-38)*frac{4}{3}*frac{1}{2}=\(frac{5}{6}-38)*frac{2}{3}=\frac{5}{6}*frac{2}{3}-38*frac{2}{3}=\frac{5}{3}*frac{1}{3}-frac{76}{3}=\frac{5}{9}-frac{76}{3}=frac{5}{9}-frac{228}{9}=-frac{223}{9}$