Question

Решение уравнение
x\x+1+x\x-1=0

Answer 1

$\frac{x}{x+1} +\frac{x}{x-1}=0\\ \\\frac{x(x-1)+x(x+1)}{(x+1)(x-1)} =0\\\\\frac{x^2-x+x^2+x}{(x+1)(x-1)}=0\\\\\frac{2x^2}{x^2-1}=0$

ОДЗ:

$x^2-1\neq 0\\\\x^2\neq 1\\\\x\neq 1; x\neq -1$

Корни уравнения:

$2x^2=0\\\\x^2=0\\\\x=0$

Ответ:0