Question

Решение уравнение 12-(4-x)в квадрате=x(5-x)

Answer 1

$12-(4-x)^2=x(5-x)\12-(16-8x+x^2)=5x-x^2\12-16+8x-x^2=5x-x^2\12-16+8x=5x\-4+8x=5x\8x-5x=4\3x=4;;|:3\ boxed{x= frac{4}{3} }$