Question

решение пожалуйста можно???

Answer 1

12^(1+log12 4) = 12^1 * 12^(log12 4) = 12 * 4 = 48

7^(2+log7 3) = 7^2 * 7^(log7 3) = 49 * 3 = 147

log2 5 + log2 85 = log2 (5 * 85) = log2 8 = lg2 2^3 = 3 * log2 2 = 3  * 1 = 3

Answer 2

1.

$12^{log_{12}{12}+log_{12}{4}}=\12^{log_{12}{(12*4)}}=\48.$

2.

$7^{log_{7}{7^2}+log_{7}{3}}=\7^{log_{7}{49*3}}=\147.$

3.

$log_{2}{5}+log_{2}{8/5}=\log_{2}{5*8/5}=\log_{2}{2^3}=3*log_{2}{2}=\3$

Ответ: 1. 48; 2. 147; 3. 3.