Question

Решение без sec и т.д!!!!

Answer 1

$\int \frac{dx}{cos^2xsin^2x}=\int \frac{\frac{1}{cos^2x}}{sin^2x}dx=\int \frac{tg^2x+1}{sin^2x}dx\\\int \frac{dx}{cos^2x}+\int \frac{dx}{sin^2x}=tgx-ctgx+C$