Question

разложите на множители:

 81(2k+1)2-(k-3)2

(8p-5)2-9(3p+2)2

Answer 1

$81(2k+1)^2-(k-3)^2=(9(2k+1))^2-(k-3)^2=(18k+9)^2-(k-3)^2=(18k+9+k-3)(18k+9-k+3)=(19k+6)(17k+12)$

 

 

$(8p-5)^2-9(3p+2)^2=(8p-5)^2-(3(3p+2))^2=(8p-5)^2-(9p+6)^2=(8p-5+9p+6)(8p-5-9p-6)=(17p+1)(-p-11)$